Correct answer: Ba41...Kf5[a] 2.Nd6#[A] 1...Kd3/[б]/ 2.Bg6#[Б] 1...Kf3 2.Bc6# 1...Kd5 2.Nf6# 1.Kd7? zz 1...Kf5[a] 2.Nd6#[A] 1...Kd3/[б]/ 2.B