Correct answer: Qb11...e1Q[a]/e1R[a] 2.Qd5#[A] 1...e1N/[б]/ 2.Qh6#[Б] 1...Nc1/Nc3 2.Q:c1# 1...e1B 2.Qh6#[Б]/Qd5#[A] 1.Nc4+?? 1...Kd3 2.Q
