Correct answer: Qh71...Bg7[a]/Bh6/[б]/ 2.Qb8#[A] 1...B:e7+[c] 2.f:e7#[Б] 1.Qg8?? (2.Qg3#) 1...Bg7[a]/Bh6/[б]/ 2.Qb8#[A] but 1...B:e7+[c]! 1.Qg7?? (2.Q<