Correct answer: Qd31...Bb7[a] 2.b5#[A] 1...d5/[б]/ 2.Q:d7#[Б] 1...Kb7 2.Qb5# 1.Ba7? zz 1...Bb7[a] 2.b5#[A] 1...d5/[б]/ 2.Q:d7#[Б] but 1...Kb7! 1.Kc8?? (2.b5#[A])
