Correct answer: Bd51...Ng2[a]/Ng6[a]/Nh3[a]/Nh5[a]/Nfe2[a]/Ne6[a]/Nd3[a]/Nfd5/[б]/ 2.Ne6#[A] 1...Nd1[c]/Ncd5[d]/Nce2[c]/Ne4[e]/Nb1[c]/Nb5[c]/
