Correct answer: Rd51...g:h3[a] 2.R:h3#[A] 1...g3/[б]/ 2.h:g3#[Б] 1...Bd5/Be4/Bf3/Bg2/Bh1/Bd7/Be8/Bb5/Ba4 2.R:h6# 1...h5 2.Ng6# 1.Be8? zz 1...g:
