Correct answer: Nd51...Kf3[a]/f5[c]/g5 2.Qe2#[A] 1...Kf5/[б]/ 2.Qe6#[Б] 1.Bg8? zz 1...Kf3[a]/f5[c] 2.Qe2#[A] 1...Kf5/[б]/ 2.Qe6#[Б] but 1...g5! 1.Qb3? zz
