Correct answer: Rh51...f:g6[a] 2.Be7#[A] 1...N:g6/[б]/ 2.Bg7#[Б] 1...K:g6 2.Rh6# 1.Bh6?? zz 1...f:g6[a] 2.Bg5# 1...N:g6/[б]/ 2.Bg5#/Bg7#[Б] but 1...K:g6