Correct answer: B:c41...f2[a] 2.R3:c4#[A] 1...Rf5/[б]//Rf6[c]/Rf7[c]/Rf8[c] 2.R5:c4#[C] 1...Nh4/Ne1/N:e3 2.Q:f4#[Б] 1.Rd3? (2.Ng5#) 1...Rf5/[б]/
