Correct answer: B:c51...c:b3[a] 2.Rb:c5#[A] 1...c:d3/[б]/ 2.Rd:c5#[Б] 1.Rb4? zz 1...c:b3[a] 2.Rc4#[C] 1...c:d3/[б]/ 2.R:c5#[D] but 1...c:b4! 1.Rd4? zz 1...c:b3[a] 2.R:c5#[D
