Correct answer: Qh11...N:d3[a]/Ne2/[б]//Nb3[c]/Na2[a] 2.Qb3#[A] 1...d:c3[d] 2.Nf4#[Б] 1...Nd6/Ne7/Nb6/Na7 2.Nb6# 1...b:a4 2.c4# 1...Bf4/Bg3/Bh2/