Correct answer: Qh61...Kd5[a]/Bh2/[б]//Bf2/[б]//Be1/[б]//Bf4/[б]/ 2.Qc4#[A] 1...d5[c] 2.Qc5#[Б] 1...d2 2.Q:d2# 1.Qc2? zz 1...Kd5[a] 2.Qc4#[A] 1...B