Correct answer: Bd31...Kf2[a] 2.Ng4#[A] 1...Kd4/[б]/ 2.Ne2#[Б] 1...Kf4 2.Nd5#/Ne2#[Б] 1...Kd2 2.Nc4# 1.Qd7?? zz 1...Kf2[a] 2.Qd4#/Qd2#/N
