Correct answer: Qf41...Kc4[a] 2.Na6#[A] 1...Nh2/Nh6/Nf2/Nf6/Ne5/[б]/ 2.N:e3#[Б] 1...d6[c] 2.Qf7#[C] 1.Kb8? zz 1...Kc4[a] 2.Na6#[A] 1...Nh2/<
