Correct answer: Qc11...K:e5[a] 2.Qg3#[A] 1...K:c5/[б]/ 2.Bb4#[Б] 1.Bc1? zz 1...K:e5[a] 2.Qg3#[A] 1...K:c5/[б]/ 2.Ba3#[C] but 1...d2! 1.Kc8?? zz 1...