Correct answer: c51...Nb4[a]/Nb8[a]/Nc5/Nc7[a] 2.Nc5#[A] 1...f5/[б]/ 2.Qd5#[Б] 1...f6 2.g8Q#/g8B# 1...Ng1/N:g5/Nh2/Nh4/Ne1/Nd2/Nd4 2.N