Correct answer: Qf71...Q:a3[a]/Qc3/[б]//Qd3[c]/Qe3[a] 2.Qg2#[A] 1...Qf3[d] 2.Qe5#[Б] 1...Nh3/Nf3/Ne2 2.Ne2# 1.Kg7?? (2.Qg2#[A]) 1...Qf3[d]
