Correct answer: Bd51...Ne6[a]/Nf7/[б]//Nc6/[б]//Nb7/[б]/ 2.Nc6#[A] 1...Ng2[c]/Ng6[c]/Nf3[d]/Nf5[c] 2.Nf5#[Б] 1.Be6? zz 1...Nf7/[б]//Nc6/[б]//N