Correct answer: Bd31...c4[a] 2.Bc6#[A] 1...Nc3/[б]/ 2.Qd2#[Б] 1...Nf6/Ng7/Nc7 2.Nc7# 1...Nf4/Ng1/Ng3/Nd4/Nc1 2.N:f4# 1.Kb1?? zz 1...c4[a