Correct answer: d41...B:f2[a] 2.Ng5#[A] 1...Nd3+/[б]//Na2[c] 2.R:d3#[Б] 1...Rh2/Rh4/R:h5/Rg3 2.Rg3# 1...Bh2 2.Q:h1# 1...Bg2 2.Rf4# 1...g:h5/g5
