Correct answer: Bd71...Rh5/Rh6[a]/Rh7/Rh8 2.Q:g4#[A] 1...f2/[б]/ 2.Bg2#[Б] 1...Bf2[c]/Be3[c]/Bd4[c]/Bc5[c]/Bb6[c] 2.R:h2#[C] 1.B:h2? zz 1...R<