Correct answer: Qb41...Kf5[a]/Bc6[c]/B:d7[c] 2.Qh7#[A] 1...K:d5/[б]/ 2.Bf3#[Б] 1.Bg4? zz 1...K:d5/[б]/ 2.Bf3#[Б] 1...Bc6[c]/B:d7[c] 2.Qh7#[A] but 1
