Correct answer: Nc81...Nc6[a]/Nd3[a]/Nd5[a]/Na2[a]/Na6[a] 2.Qd5#[A] 1...d3/[б]/ 2.Q:c5#[Б] 1...B:d6[c]/B:b6[d] 2.Q:b5#[C] 1.Qe5? zz 1...Nc6[a]/Nd
