Correct answer: Rfd11...Qc3[a] 2.R:c3#[A] 1...Qc2/[б]/ 2.R:c2#[Б] 1...d:e4/d4 2.Rf5# 1...Q:c1 2.R:c1# 1.Kg3? zz 1...Qc3+[a] 2.R:c3#[A] 1...Qc2/[б]/ 2.