Correct answer: Be41...Nf6/Nd6[a] 2.Qc5#[A] 1...Ng4/Nh1/Nh3/Ne4/[б]//N:d1 2.R:d3#[Б] 1...f3 2.e3# 1.B:d3[D]? zz 1...Nd6[a] 2.Qc5#[A] 1...Ne4
