Correct answer: Qc21...Rd4[a]/Rb3[a]/Ra3[a] 2.d3#[A] 1...Rd5/[б]/ 2.d4#[Б] 1...Rc3[c] 2.d:c3#[C] 1...Re3[d] 2.d:e3#[D] 1...d5[e] 2.Qc7#[E] 1...g:h5 2.Rf5# 1...g3 2.Rh4# 1...
