Correct answer: Qg71...Ke3/c3[a] 2.Bb6#[A] 1...Nh4/[б]//Nh8/[б]//Nf8/[б]//Ne7/[б]/ 2.Q:f4#[Б] 1...Ba2 2.N:c2# 1.Be1? zz 1...c3[a] 2.Bf2#[C] 1...Nh4
