Correct answer: Ra11...Bf2[a]/Bd2[a]/Bc1 2.N:f2#[Б] 1...Nh3/[б]//Ne2[c] 2.Q:f3#[D] 1...f:g4 2.Qh7# 1...Ne5/Nf6+/Nf8/Nc5/Nb6/Nb8 2.Nf6#[A]
