Correct answer: Rg11...e4[a] 2.Bh5#[A] 1...Qd3+/[б]/ 2.R:d3#[Б] 1...Qc3+[c] 2.R:c3#[C] 1...Qb3+[d] 2.R:b3#[D] 1...Q:a3[e] 2.Ng1#[E] 1.Bb6? zz 1...e4[a] 2.B