Correct answer: Kb51...B:c2[a] 2.Re3#[A] 1...d4/[б]/ 2.B:c4#[Б]/Ne1# 1...Ng1/Ng5/Nf2/Nhf4 2.Nf2# 1...Nh4/Nh8/Ngf4/Nf8/Ne7 2.Ng:e5# 1...d:
