Correct answer: Qf71...Kf4[a] 2.Bd2#[A] 1...Kf6/[б]/ 2.Bd8#[Б] 1.Kd5[C]? zz 1...Kf4[a] 2.Bd2#[A] 1...Kf6/[б]/ 2.Bd8#[Б] but 1...d6! 1.Ke5? (2.Bd2#[A]
