Correct answer: Ra61...Kd6[a] 2.Bg3#[A] 1...Kb6/[б]/ 2.Ba5#[Б] 1.Kd5? (2.Ba5#[Б]) but 1...Kb6/[б]/! 1.Kb5? (2.Bg3#[A]) but 1...Kd6[a]! 1.Ra4? zz 1.
