Correct answer: Ba21...e3[a] 2.Bh7#[A] 1...Ba2/[б]/ 2.Q:a2#[Б]/B:a2#[C] 1.Qa2[Б]? zz 1...e3[a] 2.Bh7#[A] 1...B:a2/[б]/ 2.B:a2#[C] 1...Be6[c] 2.Q:e6#[D] 1
