Correct answer: Ra51...Kd5[a] 2.c6#[A] 1...d6/d5/[б]/ 2.c:d6#[Б] 1.Rbb6? zz 1...Kd5[a] 2.Rf5#[C] 1...d5/[б]/ 2.Rbe6#[D] but 1...d6! 1.Ke3?? zz 1...d6/d5/[б]/ 2.c:d6#[Б] but 1...
