Correct answer: Qh81...Kd4[a] 2.Qa4#[A] 1...d4/[б]/ 2.Q:b7#[Б] 1.Qc8? (2.Qg4#) 1...d4/[б]/ 2.Q:b7#[Б] 1...Be2[c] 2.Qf5#[C] but 1...Kd4[a]! 1.Qa7?? (2.Q