Correct answer: Ke41...Be6/Bf5[a]/Bh3/[б]//Bc8 2.Rd6#[A] 1...Bg4+/Ne6[c] 2.K:g4#[Б] 1...Be3[d] 2.K:e3#[C] 1...Q:a4[e] 2.Ke2#[D] 1...Ra6 2.Q:b5#
