Correct answer: Qd21...N:d4 2.Bc4# 1...e:d4 2.Qg5# 1...Qh2/Qg1/Qf1/Qe1/Qd1/Q:c1 2.f:e4#[A] 1.Qd1[Б]? (2.Bc4#) 1...N:d6[a]/Na3/[б]/ 2.Bg1#[
