Correct answer: Nc51...Bb5/B:a4 2.Q:d5# 1...Bc3 2.b:c3#/B:c3# 1...Bc5/Ba3 2.Bc3# 1...g:f4 2.Q:f4# 1.Bc4?? (2.Q:d3#) 1...K:c4 2.Q:d5# 1...d