Correct answer: Qa81...Be4[a] 2.Be3#[A] 1...Rd5/[б]/ 2.Rc4#[Б] 1...Ng3/Nf4 2.Q:f6# 1.Be6? (2.Rc4#[Б]) 1...Be4[a] 2.Be3#[A] 1...Bd3 2.Nb3#
