Correct answer: Qa21...f6[a] 2.Qg6#[A] 1...c4/[б]/ 2.Qb6#[Б] 1.Qb2?? (2.Qg7#) 1...e1Q/e1B 2.Qg2# 1...e1R 2.Qf2#/Qg2# 1...e1N 2.Qf2# but 1...f6
