Correct answer: Qe41...Nb3[a]/Nb7/[б]//Nc4[c] 2.Qe8#[A] 1...Nc6[d] 2.Qa6#[Б] 1...K:a4 2.Q:a5# 1.Ka3? (2.Rb4#) 1...Nb7/[б]/ 2.Qe8#[A] 1...Nc6
