Correct answer: Qh81...Kf4[a] 2.Qd4#[A] 1.Qb3? zz 1...Kf4[a] 2.Qg3#[Б] 1...Kh5/[б]/ 2.Qh3#[C] but 1...Kh4! 1.Qe2+? 1...Kf4[a] 2.Qe4#[D] 1...<
