Correct answer: Kh51...Rf8[a] 2.Qf6#/Q:f8#[A] 1...R:h8/[б]/ 2.Nh6#[Б] 1...Re8/Rd8/Rc8/Rb8/Ra8 2.Qf6# 1.Qe8? (2.Q:g8#) 1...Rf8[a] 2.Q