Correct answer: Qd71...Nd6[a]/Bc3/B:d2/[б]//Ba5 2.Ng6#[A]/Nd5#[Б] 1...Nc5 2.Ng6#[A]/Nd5#[Б]/e6# 1...B:e7+ 2.f:e7# 1...Re3 2.d:e3#/Q:e3# 1...Red1/R