Correct answer: R:b51...Nd7[a] 2.Qe4#[D]/Ne3#[A] 1...Ne6/[б]/ 2.Ne7#[Б] 1...Bg2/Bf1 2.Ne3#[A]/Ne7#[Б] 1...B:f5+ 2.Q:f5# 1...c4 2.R:b5#[C] 1...Ng4/