Correct answer: Qa51...B:e6[a] 2.Qd1#[A] 1...Qf4/Qe7/Q:g6/Qg8/Q:e6/[б]//Qe8 2.Q:f4#[Б] 1.Qa3? (2.Q:c5#) 1...B:e6[a] 2.Qd3#[C] 1...Q:e6/
