Correct answer: Kc11...Rg3[a] 2.Re3#[A] 1...Rg2+/[б]/ 2.Re2#[Б] 1...Nb2 2.Ra5# 1...Rg4 2.Q:g4# 1...Rg1 2.Re1# 1...Re6 2.Rf4# 1...Rd6+ 2.Rd4#
