Correct answer: Qe51...Rh5[a] 2.Q:h5#[A] 1...Rh8/[б]/ 2.Q:h8#[Б] 1.Qh8[Б]? (2.Q:h3#/Qa1#) 1...Rh5[a] 2.Q:h5#[A]/Qa1# 1...Rh2 2.Q:h2#/Qa1#
