Correct answer: Qb81...Kd8[a] 2.Qe7#[A] 1...Ke6/[б]/ 2.Qg4#[Б] 1...Kc6 2.Qb5# 1...c6 2.Qd6#/Qe7#[A] 1.Qa4+? 1...Kd8[a] 2.Qe8#[D] 1...Ke6/[б]/ 2.<