Correct answer: Bh61...Nc6[a] 2.Nd3#[A] 1...Nf2/Nf6/Ng3/Ng5/[б]//Nd2/Nd6 2.Na6#[Б] 1.B:e4? (2.Nd3#[A]/Na6#[Б]) 1...Nc6[a]/Nc8 2.Nd3#[
